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Editorial Team
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Editorial Team
Asked: May 11, 20262026-05-11T22:19:07+00:00 2026-05-11T22:19:07+00:00

I am learning Python for the past few days and I have written this

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I am learning Python for the past few days and I have written this piece of code to evaluate a postfix expression.

postfix_expression = "34*34*+"

stack = []

for char in postfix_expression :
    try :
        char = int(char);
        stack.append(char);
    except ValueError:
        if char == '+' :
            stack.append(stack.pop() + stack.pop())
        elif char == '-' :
            stack.append(stack.pop() - stack.pop())
        elif char == '*' :
            stack.append(stack.pop() * stack.pop())
        elif char == '/' :
            stack.append(stack.pop() / stack.pop())

print stack.pop()

Is there a way I can avoid that huge if else block? As in, is there module that takes a mathematical operator in the string form and invokes the corresponding mathematical operator or some python idiom that makes this simple?

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  1. Editorial Team
    Editorial Team
    2026-05-11T22:19:08+00:00Added an answer on May 11, 2026 at 10:19 pm

    The operator module has functions that implement the standard arithmetic operators. With that, you can set up a mapping like:

    OperatorFunctions = {
        '+': operator.add,
        '-': operator.sub,
        '*': operator.mul,
        '/': operator.div,
        # etc
    }
    

    Then your main loop can look something like this:

    for char in postfix_expression:
        if char in OperatorFunctions:
            stack.append(OperatorFunctions[char](stack.pop(), stack.pop()))
        else:
            stack.append(char)
    

    You will want to take care to ensure that the operands to subtraction and division are popped off the stack in the correct order.

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