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Home/ Questions/Q 6920079
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T10:06:08+00:00 2026-05-27T10:06:08+00:00

I am learning Python I don’t get one thing. Consider this code: class Stack:

  • 0

I am learning Python I don’t get one thing. Consider this code:

class Stack:
   def __init__(self):
        self.items = []

   def push(self, item):
       self.items.append(item)

   def pop(self):
       return self.items.pop()

   def __getitem__(self,index):
       print "index",index
       return self.items[index]

   def __len__(self):
       return len(self.items)


stack = Stack()
stack.push(2)
stack.push(1)
stack.push(0)

for item in stack:
    print item

and the output

index 0
2
index 1
1
index 2
0
index 3

Why is getitem called four times?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-27T10:06:08+00:00Added an answer on May 27, 2026 at 10:06 am

    The for loop doesn’t know how to iterate over your object specifically because you have not implemented __iter__(), so it uses the default iterator. This starts at index 0 and goes until it gets an IndexError by asking for index 3. See http://effbot.org/zone/python-for-statement.htm.

    Your implementation would be a lot simpler if you derived from list, by the way. You wouldn’t need __init__(), pop(), or __getitem__(), and push could be just another name for append. Also, since list has a perfectly good __iter()__ method, for will know how to iterate it without going past the end of the list.

    class Stack(list):
        push = list.append
    
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