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Home/ Questions/Q 433181
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Editorial Team
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Editorial Team
Asked: May 12, 20262026-05-12T20:08:55+00:00 2026-05-12T20:08:55+00:00

I am loading a file into a byte[]. By my understanding the byte[] should

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I am loading a file into a byte[]. By my understanding the byte[] should contain a specific elements of bytes (8-bit). When i print each byte, all of them are not 8-bit (i.e. they dont have the length of 8).
My Code:

FileStream stream = File.OpenRead(@"C:\Image\Img.jpg");
byte[] fileByte = new byte[stream.Length];
stream.Read(fileByte, 0, fileByte.Length);

for (int i = 0; i <= fileByte.Length - 1; i++)
{
  Console.WriteLine(Convert.ToString(fileByte[i], 2));
}

Output:

10001110
11101011
10001100
1000111
10011010
10010011
1001010
11000000
1001001
100100

I think my understanding is wrong here, Can you please let me know (or provide me some tutorial links) where I am missing this.

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  1. Editorial Team
    Editorial Team
    2026-05-12T20:08:55+00:00Added an answer on May 12, 2026 at 8:08 pm

    When converting a numeric to a string, you lose any leading zeros. (Note that all of your entries start with “1”.) You can use PadLeft to put them back in.

       FileStream stream = File.OpenRead(@"C:\Image\Img.jpg"); 
       byte[] fileByte = new byte[stream.Length]; 
       stream.Read(fileByte, 0, fileByte.Length); 
    
       for (int i = 0; i <= fileByte.Length - 1; i++) 
       { 
          Console.WriteLine(Convert.ToString(fileByte[i], 2).PadLeft(8,'0')); 
    
       }
    
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