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Home/ Questions/Q 939775
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T21:50:45+00:00 2026-05-15T21:50:45+00:00

I am loading an image using the OpenEXR library. This works fine, except the

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I am loading an image using the OpenEXR library.

This works fine, except the image is loaded rotated 180 degrees. I use the loop shown below to reverse the array but sometimes the program will quit and xcode will give me an EXEC_BAD_ACCESS error (Which I assume is the same as an access violation in msvc). It does not happen everytime, just once every 5-10 times.

Ideally I’d want to reverse the array in place, although that led to errors everytime and using memcpy would fail but without causing an error, just a blank image. I’d like to know what’s causing this problem first.

Here is the code I am using: (Rgba is a struct of 4 “Half”s r, g, b, and a, defined in OpenEXR)

Rgba* readRgba(const char filename[], int& width, int& height){
    Rgba* pixelBuffer = new Rgba[width * height];
    Rgba* temp = new Rgba[width * height];

    // ....EXR Loading code....

    // TODO: *Sometimes* the following code results in a bad memory access error. No idea why.
    // Flip the image to conform with OpenGL coordinates.
    for (int i = 0; i < height; i++){
        for(int j = 0; j < width; j++){
            temp[(i*width)+j] = pixelBuffer[(width*height)-(i*width)+j];
        }
    }

        delete pixelBuffer;

        return temp;
}

Thanks in advance!

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-15T21:50:45+00:00Added an answer on May 15, 2026 at 9:50 pm

    And here’s how you can optimize this code, to save memory and for cycles:

     Rgba* readRgba(const char filename[], int& width, int& height)
     {
        Rgba* pixelBuffer = new Rgba[width * height];
        Rgba tempPixel;
    
        // ....EXR Loading code....
    
        // Flip the image to conform with OpenGL coordinates.
        for (int i = 0; i <= height/2; i++)
          for(int j = 0; j < width && (i*width + j) <= (height*width/2); j++)
          {
            tempPixel =  pixelBuffer[i*width + j];
            pixelBuffer[i*width + j] = pixelBuffer[height*width - (i*width + j) -1];
            pixelBuffer[height*width - (i*width + j) -1] = tempPixel;
          }
    
        return pixelBuffer;
     }
    

    Note that optimal (from a memory usage best practices point of view) would be to pass pixelBuffer* as a parameter and already allocated. It’s a good practice to allocate and release the memory in the same piece of code.

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