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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T00:43:46+00:00 2026-05-26T00:43:46+00:00

I am looking for a way to allocate a 2D (m x n) matrix

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I am looking for a way to allocate a 2D (m x n) matrix on the heap where the elements are consecutive in memory. Currently I know of two ways to accomplish that:

First approach

int* M = new int[m * n];
  • Pro: The size of M can by dynamically determined.
  • Con: Indexing of M is a bit of a pain. (M[i * m + j])

Second approach

typedef int dim[2];
dim* M = new dim[n];
  • Pro: Indexing of M is just how I want it to be.
  • Con: The size of the first dimension (m) cannot be set dynamically.

Question

Is there a way to allocate a 2D matrix dynamically on the heap where I can index the elements with [i][j] and the memory allocation is consecutive?

I know it would make a lot of sense to use a class for that, but I am specifically looking for a way as described above.

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  1. Editorial Team
    Editorial Team
    2026-05-26T00:43:47+00:00Added an answer on May 26, 2026 at 12:43 am

    You can try this

    int** M = new int*[m];
    int *M_data = new int[m*n];
    
    for(int i=0; i< m; ++i) 
    {
        M[i] = M_data + i * n;
    }
    
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