Question

I am looking for an idea about a condition that stop when an integer reach to the max number of its digit..

i.e

the max number of 2 digits number is 99

the max number of 5 digits number is 99999

I got this one

while(x != ([10^number of digits] -1))
{
    x++;
}
cout << x;

but actually i am dealing with string, which may i have a huge numbers, and this code start to get very long execution time after 9 digits.

So can any one give me a good idea about that, Thanks.

Answer 1

How about:

done = false;
while(!done)
{
    x++;
    done = true;
    for (i=0 ; i<number_of_digits; i++)
       if x[i] != '9'
          done = false;
}
cout << x;