Question

I am looking for the most efficient method to do the following…

I have a table with three fields: id, eventid and movetype – and I have the following code to query the database for all entries with a matching eventid :

$get_results = mysql_query("SELECT * FROM table WHERE eventid='$eventid'");
while($row = mysql_fetch_array($get_results)){
    // store results in array
    $move_type_array = explode(" ", $row['movetype']);
}

Please note: movetype can only be three values: Internal, Outgoing, Incoming

Using a set of dummy data, var_dump($move_type_array) could output:

array(1) { [0]=> string(8) "Internal" } array(1) { [0]=> string(8) "Internal" }

Another example of an output would be:

array(1) { [0]=> string(8) "Internal" } array(1) { [0]=> string(8) "Incoming" } array(1) { [0]=> string(8) "Outgoing" }

I then need to check the output to see if the following conditions are met:

1. Does the array contain Internal twice?
2. If the array only contains Internal once, then does the array also contain Incoming and Outgoing?

If either of the conditions are met then a message should be displayed telling them which condition has been met, otherwise a message should tell them that the conditions have not been met.

I have tried using a number of PHP functions such as in_array(), and also tried storing the data in a string and using preg_match() however I was unsuccessful in both methods.

Answer 1

Try this:

$result = mysql_query("
    SELECT SUM(IF(movetype = 'Internal', 1, 0)) AS internal, 
           SUM(IF(movetype = 'Outgoing', 1, 0)) AS outgoing, 
           SUM(IF(movetype = 'Incoming', 1, 0)) AS incoming
    FROM table
    WHERE eventid = $eventid
    GROUP BY eventid
");
$count = mysql_fetch_array($result);

if ($count['internal'] >= 2 || ($count['internal'] == 1 
        && $count['outgoing'] >= 1 
        && $count['incoming'] >= 1)) {
    echo 'Yes';
} else {
    echo 'No';
}