Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
Lost your password? Please enter your email address. You will receive a link and will create a new password via email.
Please briefly explain why you feel this question should be reported.
Please briefly explain why you feel this answer should be reported.
Please briefly explain why you feel this user should be reported.
I am looking to find the last positional parameter. I know to find the number of parameters is $# which logically is the last but I need to find and use what is in the last positional parameter.
It would be like if $# = 5, I want to do $5.
I have tried to do something like $$# or ${$#} as guesses but can’t get it.
Instances where I would need to use it is in an if statement or declaring it to another variable or with echo.
I hope that is clear. Thanks in advance.
You want
${!#}, which combines the argument count with indirection.