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Home/ Questions/Q 7636319
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Editorial Team
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Editorial Team
Asked: May 31, 20262026-05-31T07:38:46+00:00 2026-05-31T07:38:46+00:00

I am making a drop down menu that is populated using an sql database.

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I am making a drop down menu that is populated using an sql database. Using the popDropDown function below, I am taking in all the needed data and creating the needed HTML for the dynamic population.

Here’s the rub… I am having a tough time returning the selected email address. I realize that the POST stuff isn’t documented here that will process my request. I would like to know if there is any way to return the email address that has been selected by the user using the drop down. The end result will use the returned address + a subject and message to generate an email.

What have I forgotten to mention? Thanks is advance.

$emailAd = popDropDown($results);


function popDropDown($results){
$_email="";
while($row=$results->fetch_assoc())
{
    $email=$row['EmailAddress'];
    $id=$row['id'];
    $Name=$row['MemberName'];

    //echo $email."<br>";
    if ($_POST['emailMenu']==$id)
        {
        echo '<option value="'.$id.'"selected>'.$email."</option>";
        $_email=$email;
        }
    else
        echo '<option value="'.$id.'">'.$email."</option>";
}
return $_email;

}
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  1. Editorial Team
    Editorial Team
    2026-05-31T07:38:47+00:00Added an answer on May 31, 2026 at 7:38 am

    Ummm. Why do it this way? If the form being posted already contains the ID of the email record you want to use, then you do NOT need to fetch all the rows and rummage through them to find the row yo uwant, you just query directly for the ONE row you know you need:

    function popDropDown() {
       $sql = "SELECT email FROM yourtable WHERE id=" . (int)$_POST['emailMenu'];
       $result = mysql_query($sql) or die(mysql_error());
       if (mysql_num_rows($result) == 0) {
           return null;
       }
       $row = mysql_fetch_assoc($result);
       return($row['email']);
    }
    
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