Question

I am making a program that is converting from decimal to binary, octal, and hexadecimal. I am only focusing on the decimal to binary part in this so far. My problems are that the binary when I ask it to convert up to said number print them vertically not horizontally like 010. Also my while statement does not stop exacution if the y input is greater than 1024, which is the highest value I want to be able to be accepted.

import java.util.Scanner;

public class DNS
{
    public static void main(String[] args)
    {
        int y;
        Scanner input = new Scanner( System.in);
    do
    {   
        System.out.println("java DisplayNumberSystems");
        System.out.println("Enter a decimal value to display to: ");
        y = input.nextInt();

        for(int x=0; x <=y; x++)
        {
            convertToBinary(x);
        }
    }
    while(y <=1024);    

    }

    public static void convertToBinary(int x)
    {
        if(x >0)
        {
            convertToBinary(x/2);
            System.out.print(x%2 + " ");

        }
        System.out.println("");
    }

}

Answer 1

remove System.out.println(""); from public static void convertToBinary(int x)
you will be able to print horizontally

and change your do-while to simple while like this

    int y;
    Scanner input = new Scanner( System.in);
    System.out.println("java DisplayNumberSystems");
    System.out.println("Enter a decimal value to display to: ");
    y = input.nextInt();

    while(y <=1024)
{   

    for(int x=0; x <=y; x++)
    {
        convertToBinary(x);
    }
}

you were checking if y<=1024 after calling convertToBinary() method. you have check if y<=1024 before making a call to convertToBinary() method.