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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T11:09:39+00:00 2026-05-23T11:09:39+00:00

I am making a RPM file cache server. A PC on the network accesses

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I am making a RPM file cache server. A PC on the network accesses the cache server. If the file is present on the server, it is served. If not, it is downloaded from the internet before being served.

I wrote this with BaseHTTPServer with urllib to fetch the files. Now with small files, there is little delay between downloading the file and serving it.

...
store_file.write(download_buffer.read())
store_file.close()
...
f=open(file_path,'r')
self.wfile.write(f.read())
...

But some files may take minutes to download. So the client is kept waiting, while server finishes the file. This may cause client to time-out. How do we serve the file as it is being downloaded to prevent time-outs by the client?

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  1. Editorial Team
    Editorial Team
    2026-05-23T11:09:40+00:00Added an answer on May 23, 2026 at 11:09 am

    A read-write loop.

    x= download_buffer.read(1024)
    while x:
        self.wfile.write(x)
        x= download_buffer.read(1024)
    
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