Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 8137345
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: June 6, 20262026-06-06T11:05:14+00:00 2026-06-06T11:05:14+00:00

I am making a simple ajax request using jquery . Below is my ajax

  • 0

I am making a simple ajax request using jquery . Below is my ajax function .

     var makeJqueryAjaxRequest = function(arrParam) {
         var request = $.ajax({
             url : arrParam['url'],
             async: false,
             type: arrParam['type'],
             data: arrParam['data'],
             dataType: arrParam['data_type'],
             success: function(data) {
                 if(data){ 
                 return data;   
                 }
             }
         });
     }

here is my function calls :

      var items = {
       "type" : 'POST',
       "url" : ajaxGetUrl,
       "data" : arrParam['data'],
       "data_type" : 'html'
      };
      var msg = makeJqueryAjaxRequest(items);

Now don’t know why my makeJqueryAjaxRequest function always returns the null value. If I alert the data in the success : I’m getting the data perfect . But when I try to return it gives me the null value

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-06-06T11:05:16+00:00Added an answer on June 6, 2026 at 11:05 am

    You can’t return value from an Asynchronous callback function.

    Because success is a async callback which is called by jQuery when a ajax Event(success in this case) fires. So returning something from this functions will not have any effect as they will be returned to jQuery code.

    You can use the following

    var makeJqueryAjaxRequest = function(arrParam) {
         var request = $.ajax({
            url : arrParam['url'],
            async: false,
            type: arrParam['type'],
            data: arrParam['data'],
            dataType: arrParam['data_type']
    
         });
       return request;
      }
    

    Then do

     makeJqueryAjaxRequest(items).done(function(data){
        if(data){
          var msg  = data;  
          // do whatever you like with msg now
        }
     });
    

    Alternative Callback Approach:

    var makeJqueryAjaxRequest = function(arrParam,callback) {
         var request = $.ajax({
            url : arrParam['url'],
            async: false,
            type: arrParam['type'],
            data: arrParam['data'],
            dataType: arrParam['data_type'],
            success: function(data) {
               if(data){ 
                  callback(data); 
               }
           }
         });
    
      }
    

    Then use it like

     makeJqueryAjaxRequest(items,function(data){
        // do whatever you like with data
     });
    

    Doc on $.ajax()

    Note

    And with either of these approach async: false is not necessary. You can remove that. As the doc says

    As of jQuery 1.8, the use of async: false is deprecated

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I am making this simple get request using jquery ajax: $.ajax({ url: https://app.asana.com/-/api/0.1/workspaces/, type:
I'm making a simple POST request via jquery's .ajax function to a routed URL
I'm making very simple ajax requests like $.ajax({ type: POST, url: atuamae.org/send.php, data: dataString,
I'm making an ajax request and I have some problems, this is my jquery
I m making an ajax call using jQuery to an ASP.NET page which acts
I am making a simple AJAX call to an external site. It works ok
I'm having trouble with this simple scenario. First, I'm using ASP.NET WebForms. I'm making
i have some simple jquery tabs: <script> $(function() { $( #tabs ).tabs(); }); </script>
After a page loads, I'm making an AJAX request to pull down an HTML
i am making simple autosuggestion (autocompleter) plugin with jQuery. Unfortunately i have to use

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.