Question

I am making a small website as my first project. I have finalized to use Java Servlets and JSP for my Server-side scripting. I am learning it from O’Reilly’s HeadFirst Servlets and JSP. I decided to use Apache-Tomcat as my web server and container. I downloaded it. I even have jdk 1.6 update 21.
I unzipped apache in C:
It is running successfully as i get the default Tomcat home page when I type http://localhost:8080 in my browser.

In chapter 3 there is a small project called beer.
So I tried to make it.
I created a directory called beer under webapps C:\apache-tomcat-7.0.0\webapps\beer. Inside it to just check the basics I created a html file called form.html. But when I try to access it via the browser http://localhost:8080/beer/form.html I get the following error:

HTTP Status 404 – /beer/form.html

type Status report

message /beer/form.html

description The requested resource
(/beer/form.html) is not available.

Apache Tomcat/7.0.0

I have even tried using tomcat 6, but to no use.

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Thank you for replying…
Actually my doubt is..that here i am trying to access a .html file which is not a servlet so does it even require a Deployment description????

well, there is only 1 servlet i planned to make (initially)….the one which is mentioned in the form (action= “….”) in the html file i made….
so i thought of checking the basic html file before i deployed a servlet….btw…if i have to include the html file also in the DD, then what should i write in place of ServletName in the xml code u gave?
here are the contents of my web.xml (i modified it as u said…but dunno what to write in the Servlet Name)

<?xml version="1.0" encoding="utf-8"?>
 <web-app xmlns="http://java.sun.com/xml/ns/j2ee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd" version="2.4">
    <servlet>
        <servlet-name>html page</servlet-name>
        <servlet-class>form</servlet-class>
    </servlet>
    <servlet-mapping>
      <servlet-name>html page</servlet-name>
      <url-pattern>/beer/form.html</url-pattern>
   </servlet-mapping>


    <servlet>
        <servlet-name>Ch3 Beer</servlet-name>
        <servlet-class>com.example.web.BeerSelect</servlet-class>
    </servlet>
    <servlet-mapping>
        <servlet-name>Ch3 Beer</servlet-name>
        <url-pattern>/SelectBeer.do</url-pattern>
    </servlet-mapping>
</web-app>

Answer 1

It should work just fine. Probably a typo in URL or filename. It’s case sensitive as well. /Beer is not the same as /beer. Doublecheck the URL. Also, don’t you have multiple instances of Tomcat running or extracted from the downloaded zip? You might have placed the new page in the wrong one and/or be running the wrong one. Try shutting down the Tomcat instance you think you’re running and reload the homepage in the webbrowser. If the homepage doesn’t disappear, then it’s a different one.