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Home/ Questions/Q 8008107
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Editorial Team
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Editorial Team
Asked: June 4, 20262026-06-04T18:02:16+00:00 2026-06-04T18:02:16+00:00

I am making a video playback website and I need to use a html5

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I am making a video playback website and I need to use a html5 video player to play local videos and youtube api and vimeo api to play vimeo videos. THE problem is I want to filter the link entered by the user for all 3 conditions. I tried some regex as I never used it before but was not successful. Can anyone help me giving a example showing how to separate those links for making 3 conditions

  1. taking out the word “youtube” out of a youtube link so that i could make a condition statement

  2. same way taking out .mp4 and .ogg extension from the local video so that it can be used to be played in a html5 video player

  3. same way extract the word “vimeo” from a vimeo link so that I can use a vimeo api to play vimeo videos.

Can anyone help?

For example we input a youtube link

http://www.youtube.com/watch?v=example

Then how to get the word “youtube” out of this link?

And I uploaded a local video with file name

example.mp4

Then how can I get the extensoon mp4 from that?

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  1. Editorial Team
    Editorial Team
    2026-06-04T18:02:17+00:00Added an answer on June 4, 2026 at 6:02 pm

    This is adapated from a php class I wrote some times ago :

    <?php
    
    function identifyService ( $url )
    {
        $url = preg_replace('#\#.*$#', '', trim($url));
    
        $services_regexp = array(
            "#^\w+\.(?P<format>[a-zA-Z0-9]{2,5})#"                     => 'local',
            '#vimeo\.com\/(?P<id>[0-9]*)[\/\?]?#i'                     => 'vimeo',
            '#youtube\.[a-z]{0,5}/.*[\?&]?v(?:\/|=)?(?P<id>[^&]*)#i'   => 'youtube'
        );
    
        foreach ( $services_regexp as $pattern => $service ) {
            if ( preg_match ( $pattern, $url, $matches ) ) {
                return ( $service === 'local' ) ? $matches['format']  : $service;
            }
        }
    
        return false;
    
    }
    
    
    $url = "foo.ogg";
    // $url = "bar.mp4";
    // $url = "http://www.youtube.com/watch?v=_rqR8_mOp_A";
    // $url = "http://vimeo.com/39044814";
    $service  = identifyService( $url );
    var_dump( $service );
    
    
    ?>
    

    Hope it helps.

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