Question

I am making an app in which i have to encrypt the data and send it to server and in that case while converting data to int form i am getting number format exception .My code is as follows:

 public String encryptData(String key, String s)
    {
        try{
        System.out.println("encrypt");     
   //    byte[] utf8 = data.getBytes("UTF8");
         byte[] fin=s.getBytes();
         System.out.println("encrypt2");
     //   byte[] enc = ecipher.doFinal(fin);
         System.out.println("encrypt3");
        }catch (Exception e) {
            System.out.println(e);
        }
         System.out.println("1");
         int keyLen = key.length();
      //  int dataLen = Convert.ToInt16(data.length());
         System.out.println("2");
        Integer dataLen=Integer.parseInt(s);  // **This line is giving exception**
        System.out.println("3");
        char chData;
        char chKey;
        char[] data1 = s.toCharArray();
        char[] key1 = key.toCharArray();
        System.out.println("4");
        StringBuilder encryptedData = new StringBuilder();
        for (int i = 0; i < dataLen; i++)
        {
            chData = data1[i];
            for (int j = 0; j < keyLen; j++)
            {
                chKey = key1[j];
                chData = (char)(chData ^ chKey);
            }
            encryptedData.append(chData);
        }
       return (encryptedData.toString());
    }

and My xml is :

xml="<?xml version='1.0' encoding='utf-8'?>" + "<admin_auth_req><user_name>" +username+ "</user_name>" + "<password>" +PWOrd+ "</password></admin_auth_req>";

Exception is:

java.lang.NumberFormatException: unable to parse '<?xml version='1.0' encoding='utf-8'?><admin_auth_req><user_name>newuser</user_name><password>tester</password></admin_auth_req>' as integer


                                 `

Answer 1

You are triying to convert a String value which is not a number representation into String. What you really should do is to find the length of the String. So change this line:

Integer dataLen=Integer.parseInt(s);

to:

int dataLen = s.length();