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Home/ Questions/Q 7795941
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Editorial Team
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Editorial Team
Asked: June 1, 20262026-06-01T23:13:02+00:00 2026-06-01T23:13:02+00:00

I am making XMLHttpRequest to call Google search API URL. And on getting the

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I am making XMLHttpRequest to call Google search API URL. And on getting the response I want to call another result Handling function. But I also want to pass the parameter to it.

request = new XMLHttpRequest();

if(request) {
    var url = "http://localhost:8080/final_project/SearchService";
    url += "?user_query=" + getQueryString();

    request.onreadystatechange = handleSearchResult;
    request.open("GET", url, true);
    request.send(null);
}

Here handleSearchResult is resultHandler and I want to pass parameter to this function. But if I do so the function gets called directly.

What can be done to solve this problem?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-01T23:13:05+00:00Added an answer on June 1, 2026 at 11:13 pm

    Surround it using a closure:

    request.onreadystatechange = function() {
      handleSearchResult(yourParameter);
    }
    
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