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Home/ Questions/Q 3349290
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Editorial Team
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Editorial Team
Asked: May 18, 20262026-05-18T01:38:46+00:00 2026-05-18T01:38:46+00:00

I am new at JQuery and I have a specific question about the IF-THEN-ELSE

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I am new at JQuery and I have a specific question about the IF-THEN-ELSE fork.
The big problem for me is the syntax of this (I suck at Javascript). It would help me if anyone can “translate” the pseudo code into a JQuery (or Javascript) valide code.

The pseudo code:

IF “#Contentshowroom” css “left” is NOT > 1960px

THEN
On Click “#Forwardbutton” DO
animate “#Contentshowroom” css “left” =+980px

ELSE You can not click on the “#Forwardbutton”

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-18T01:38:46+00:00Added an answer on May 18, 2026 at 1:38 am

    click doc
    animate doc
    offset doc

    $("#Forwardbutton").click( function( e ){
    
       // lookup is safe, no noticable performance cost.
       // though a reference makes it more losely coupled.
       // I'll leave it at your discretion.
       var target = $("#Contentshowroom")
       // NOTE: the offset parent should have position relative or absolute.
       , leftPos = target.offset().left; 
    
       if ( leftPos < 1960 ) {
    
          target.animate({
             left : leftPos + 980
          }); // see docs to tweak animation
    
       } // else do nothing.
    
    } );
    

    Could also use e.preventDefault(); , but don’t if it’s not needed, it will safe you headaches if you add more listeners to your buttons and find out they’re not working.

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