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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T14:04:36+00:00 2026-05-27T14:04:36+00:00

I am new at this and stuck for days…trying everything I could find from

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I am new at this and stuck for days…trying everything I could find from Google and these Forums.

I have one MySQL table that I need to pull data from.

I need to pull all records where AgentID = 1234
Also, pull all records where OfficeID = 4321 (and AgentID != 1234 to prevent dupes)
Then display the results with AgentID records first, if they exist, then the OfficeID records.

I tried a UNION, but could not find a way to sort or show Agent first, Office second.
Tried array_merge and two queries/results, but the merged data was mixed instead of Agent First data, again, with no way to sort by Agent first.

Any ideas would be greatly appreciated!

Bill

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  1. Editorial Team
    Editorial Team
    2026-05-27T14:04:36+00:00Added an answer on May 27, 2026 at 2:04 pm

    You can use a CASE statement in the ORDER BY to impose your specified conditions.

    SELECT *
        FROM YourTable
        WHERE AgentID = 1234
            OR (OfficeID = 4321 AND AgentID <> 1234)
        ORDER BY CASE WHEN AgentId = 1234 THEN 0 ELSE 1 END,
                 AgentID, OfficeID
    
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