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Home/ Questions/Q 7717349
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Editorial Team
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Editorial Team
Asked: June 1, 20262026-06-01T02:52:31+00:00 2026-06-01T02:52:31+00:00

I am new to bash scripting and trying to learn a few things. Here

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I am new to bash scripting and trying to learn a few things. Here is the code I have tried:

n=$1
shift

echo "Printing your name $n times"
count=1
for ((i=1;i<=$n;i++))
do
    echo $@ -$i
    count='expr[$count+1]'
done

echo 'New Model'
count=1
while ["$count" -le "$n"]
do
    echo $@ -$i
    count='expr[$count+1]'
done

The for loop works fine, but the while loop is not printing the desired result. the Result of the for loop and while should be the same. Could you please tell me where I have gone wrong. Thank you.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-01T02:52:33+00:00Added an answer on June 1, 2026 at 2:52 am

    One problem is that you need spaces around the brackets, so that bash knows that they’re separate words. That is, change this:

    while ["$count" -le "$n"]
    

    to this:

    while [ "$count" -le "$n" ]
    

    Another is that this:

    count='expr[$count+1]'
    

    actually sets the variable count to the specific string expr[$count+1]. What you seem to mean is this:

    count=$((count+1))
    

    which increases the value of count by 1.

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