Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 619453
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 13, 20262026-05-13T18:39:25+00:00 2026-05-13T18:39:25+00:00

I am new to C++ and I am trying to understand some code. What

  • 0

I am new to C++ and I am trying to understand some code. What does it mean to have a * in front of the datatype ? and why is the class Name in front of the method name CAStar::LinkChild

void CAStar::LinkChild(_asNode *node, _asNode *temp)
{

}
  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-13T18:39:26+00:00Added an answer on May 13, 2026 at 6:39 pm
    1. A * in front of the data type says that the variable is a pointer to the data type, in this case, a pointer to a node. Instead of passing a copy of the entire “node” into the method, a memory address, or pointer, is passed in instead. For details, see Pointers in this C++ Tutorial.

    2. The class name in front of the method name specifies that this is defining a method of the CAStar class. For details, see the Tutorial pages for Classes.

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

New programmer here, I am trying to understand and break down this code below
I'm rather new to C++ and I'm trying to understand the code over on
I am trying to understand some code. It is a small program that prints
I'm trying to understand some code I found the open source oauth-php library. The
I`m trying to display classes that have properties of type some custom class inside
I am new to Dojo and trying to understand how to handle events. There
I'm new to git and I'm trying to understand if it can solve my
I'm new to iOS development and I'm trying to understand if is it's possible
I'm relatively new to Java and I'm still trying to understand the fundamentals. I
I'm really new to OOP and C# and I'm trying to understand, how I

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.