Question

I am new to C++ . I am writing following simple code. I wanted to pass the character[40] into a function and then get the same as output.
If i put a debug at following point.
strcpy_s(x,100,tester);

But it only takes “This” if i write “This is sent at the output”. Can anyone please point out what am i missing and whats the reason for only accepting few characters.

// BUSTesting.cpp : Defines the entry point for the console application.
//

#include "stdafx.h"
#include <iostream>
#include "resource.h"

int testFunction(char* tester);
int _tmain()
{

    char m[40];
    std::cin>>m;
    testFunction(m);
}
int testFunction(char* tester)
{

    char x[100] ;
    memset(x,100,sizeof(x));
    strcpy_s(x,100,tester);
    std::cout<<x;
    return 0;
}

Answer 1

operator>> will stop consuming input at first whitespace character. An alternative would be to use cin.getline() to prevent processing of input due to whitespace.

Note to initialize an array and avoid memset():

char x[100] = "";

Recommend std::string and std::getline() which avoids specifying a maximum number of characters to read from the input stream (avoiding potential buffer overrun problems with fixed sized arrays).