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Home/ Questions/Q 6877281
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T04:34:54+00:00 2026-05-27T04:34:54+00:00

I am new to C++, I coded in Java for an year. The equivalent

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I am new to C++, I coded in Java for an year. The equivalent in C++ for interfaces and abstract classes alike is only abstract classes. Is that supposed to be a handicap while doing factory design? There are many times I want to leave out the defining the methods to the inheriting classes and I want to enforce that.

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  1. Editorial Team
    Editorial Team
    2026-05-27T04:34:54+00:00Added an answer on May 27, 2026 at 4:34 am

    Java interfaces are best translated as C++ abstract classes. In Java (as far as I know) a interface is merely a subset of an abstract class anyway, except it allows “multiple inheritance” which C++ has in all cases anyway.

    class thing_interface {
    public:
        virtual ~thing_interface() {}
        virtual void foo() =0; //pure virtual function
    };
    class other_interface {
    public:
        virtual ~other_interface () {}
        virtual void bar() =0; //pure virtual function
    };
    
    class thing_impl : public thing_interface, public other_interface { 
    protected:
        int member;
    public:
        thing_impl() : member(0) {}
        virtual ~thing_impl() {};
        virtual void foo() { std::cout << "FOO!\n";}
        virtual void bar() { std::cout << "BAR!\n";}
    };
    

    The =0 syntax means it is not defined in the interface, but must be defined in classes that fulfill the interface. Also note that if you have any virtual function, you almost always want a virtual destructor as well. C++ will tell you an error if you try to make a thing_interface by itself, since there’s no implementation functions.

    It’s not really a handicap, since I can’t think of anything Java can do here that C++ can’t.

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