I am new to C++ (just starting). I come from a Java background and I was trying out the following piece of code that would sum the numbers between 1 and 10 (inclusive) and then print out the sum:
/*
* File: main.cpp
* Author: omarestrella
*
* Created on June 7, 2010, 8:02 PM
*/
#include <cstdlib>
#include <iostream>
using namespace std;
int main() {
int sum;
for(int x = 1; x <= 10; x++) {
sum += x;
}
cout << "The sum is: " << sum << endl;
return 0;
}
When I ran it it kept printing 32822 for the sum. I knew the answer was supposed to be 55 and realized that its print the max value for a short (32767) plus 55. Changing
int sum;
to
int sum = 0;
would work (as it should, since the variable needs to be initialized!). Why does this behavior happen, though? Why doesnt the compiler warn you about something like this? I know Java screams at you when something isnt initialized.
Thank you.
Edit:
Im using g++. Here is the output from g++ –version:
Im on Mac OS X and am using g++.
nom24837c:~ omarestrella$ g++ --version
i686-apple-darwin10-g++-4.2.1 (GCC) 4.2.1 (Apple Inc. build 5646)
Because it’s not part of the C++ standard. The variable will just take whatever value is currently sitting in the memory it’s assigned. This saves operations which can sometimes be unnecessary because the variable will be assigned a value later.
It’s interesting to note and very important for Java/.Net programmers to note when switching to C/C++. A program written in C++ is native and machine-level. It is not running on a VM or a some other sort of framework. It is a collection of raw operations (for the most part). You do not have a virtual machine running in the background checking you variables and catching exceptions or segfaults for you. This is a big difference which can lead to a lot of confusion in the way C++ handles variables and memory, as opposed to Java or a .Net language. Hell, in .Net all your integers are implicitly initialised to 0!