Question

I am new to Django. I would like to run some command from some view. Something like:

 python /path/to/the/script/run.py -id 11 --user root --run_digital_id 29 --workflow map --lib_group library.yaml --log log.conf

I use this method to call:

def run_in_background(cmd):
    logging.info('running ' + cmd)
    p = subprocess.Popen(cmd, shell=True, stdout=PIPE, stderr=PIPE)
    output, errors = p.communicate()
    print output
    print errors
    logging.debug(output)
    logging.debug(errors)

The command is passed to the method run_in_background(). When I copy the command and run on the terminal, it works well. But when I run it from some view of Django, it reports:

Traceback (most recent call last):
  File "/path/to/the/script/run.py", line 11, in ?
    import conf, util
  File "/path/to/the/script/conf.py", line 11
    class Settings():
                   ^
SyntaxError: invalid syntax

Er, the run_in_background method is also working when I call it from some ‘plain’ python code.

The error position is the first line of my program. I suspect there is something wrong with the paths… But after searching for long time, I did not get the reason. Please help. Thanks.

Answer 1

Seems like this is the solution!

In some python version defining class with empty parenthesis like class Settings(): is not valid, you may want to change it to class Settings(object):