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Home/ Questions/Q 6103557
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T13:44:32+00:00 2026-05-23T13:44:32+00:00

I am new to java.util.concurrent package and wrote a simple method which fetches some

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I am new to java.util.concurrent package and wrote a simple method which fetches some rows from DB. I made sure that my DB call throws back an exception to handle it. But i am not seeing the exception propagating back to me. Instead call to my method is returning null.

Can some one help me in this case? Here is my sample method call

private FutureTask<List<ConditionFact>> getConditionFacts(final Member member) throws Exception {
        FutureTask<List<ConditionFact>> task = new FutureTask<List<ConditionFact>>(new Callable<List<ConditionFact>>() {
            public List<ConditionFact> call() throws Exception {
                return saeFactDao.findConditionFactsByMember(member);
            }
        });
        taskExecutor.execute(task);
        return task;
    }

I googled and found some pages around it. But don’t see any concrete solutions for it. Experts please help….

The taskExecutor is object of org.springframework.core.task.TaskExecutor

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  1. Editorial Team
    Editorial Team
    2026-05-23T13:44:33+00:00Added an answer on May 23, 2026 at 1:44 pm

    The FutureTask will execute in a new thread and, if an exception occurs, will store it in an instance field. It’s only when you’ll ask the result of the execution that you will get the exception, wrapped inside an ExecutionException:

    FutureTask<List<ConditionFact>> task = getConditionFacts(member);
    // wait for the task to complete and get the result:
    try {
        List<ConditionFact> conditionFacts = task.get();
    }
    catch (ExecutionException e) {
        // an exception occurred.
        Throwable cause = e.getCause(); // cause is the original exception thrown by the DAO
    }
    
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