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Home/ Questions/Q 6934447
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T11:57:41+00:00 2026-05-27T11:57:41+00:00

I am new to php, i created drop down which calling data from mysql

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I am new to php, i created drop down which calling data from mysql data base, user selects option and its save to data base.

Problem Arises in edit form in which its do not showing selected value.

Drop Down code is below:

$query = 'SELECT name FROM owner';
$result = mysql_query($query) or die ('Error in query: $query. ' . mysql_error());

//create selection list
echo "<select name='owner'>\name";
while($row = mysql_fetch_row($result))
{
    $heading = $row[0];
    echo "<option value='$heading'>$heading\n";
}
echo "</select>"

Please advise solution for the edit form.

Thanks in Advance

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  1. Editorial Team
    Editorial Team
    2026-05-27T11:57:41+00:00Added an answer on May 27, 2026 at 11:57 am
    $query = 'SELECT name FROM owner';
    $result = mysql_query($query) or die ('Error in query: $query. ' . mysql_error());
    
    //create selection list
    echo "<select name='owner'>\name";
    while($row = mysql_fetch_row($result))
    {
        $heading = $row[0];
    ?>
        <option <?php if($heading=="SOMETHING") { echo "selected='selected'"; } ?> value="SOMETHING">SOMETHING</option>
    <option <?php if($heading=="SOMETHING2") { echo "selected='selected'"; } ?> value="SOMETHING2">SOMETHING2</option>
    <option <?php if($heading=="SOMETHING3") { echo "selected='selected'"; } ?> value="SOMETHING3">SOMETHING3</option>
    <?php
    }
    echo "</select>"
    
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