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Home/ Questions/Q 6602679
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T18:54:18+00:00 2026-05-25T18:54:18+00:00

I am new to Python. I am working on gps files. I need to

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I am new to Python. I am working on gps files. I need to convert a CSV file having all the gps data to kml file. Below is the code in python I am using :

import csv
#Input the file name.
fname = raw_input("Enter file name WITHOUT extension: ")
data = csv.reader(open(fname + '.csv'), delimiter = ',')
#Skip the 1st header row.
data.next()
#Open the file to be written.
f = open('csv2kml.kml', 'w')

#Writing the kml file.
f.write("<?xml version='1.0' encoding='UTF-8'?>\n")
f.write("<kml xmlns='http://earth.google.com/kml/2.1'>\n")
f.write("<Document>\n")
f.write("   <name>" + fname + '.kml' +"</name>\n")
for row in data:
    f.write("   <Placemark>\n")
    f.write("       <name>" + str(row[1]) + "</name>\n")
    f.write("       <description>" + str(row[0]) + "</description>\n")
    f.write("       <Point>\n")
    f.write("           <coordinates>" + str(row[3]) + "," + str(row[2]) + "," + str(row[4]) + "</coordinates>\n")
    f.write("       </Point>\n")
    f.write("   </Placemark>\n")
f.write("</Document>\n")
f.write("</kml>\n")
print "File Created. "
print "Press ENTER to exit. "
raw_input()

The csv file I am using is available here : dip12Sep11newEdited.csv
The kml file generated is available here : csv2kml.kml
But the kml file is not getting created correctly. Apparently after some rows in the csv the code is not able to generate more Placemarks. Its not able to iterate. You can see that by scrolling to the last part of the kml file generated.

Can anyone help me finding out the error in the code, because for some smaller csv files it worked correctly and created kml files fully.

Thanks.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-25T18:54:19+00:00Added an answer on May 25, 2026 at 6:54 pm

    You didn’t answer the query above, but my guess is that the error is that you’re not closing your output file (which would flush your output).

    f.close()
    
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