Question

I am new to QT Creator. I did create a menu: Login || Open. When login is clicked I would like to see a line edit and a press button. When Open is clicked I would like to see a picture in the window. Can I change the interface of the same window depending on what I click in the menu bar? How can I do that?

Answer 1

I did something similar to this – an app with several major areas, toggled by an icon bar at the top.
I used a QStackWidget to stack the different application areas on top of each other, a set of QActions that I created using the designer, and a QActionGroup to implement the toggling.
When the actions are marked as “checkable” and grouped in a QActionGroup, theQToolBar only lets one be active at the time.

Here’s a simplified extract of my code:

// MyApp.h
#include <QMainWindow>    
class QAction;
class QActionGroup;

namespace Ui {
    class MyApp;
} 

class MyApp: public QMainWindow
{    
    Q_OBJECT

public:
    explicit MyApp(QWidget *parent = 0);
    ~MyApp();

public slots:
    void showSection(QAction* a);

private:
    Ui::MyApp *ui;
    QActionGroup* sections;
};

 

//MyApp.cpp
#include "structureapp.h"
#include "ui_structureapp.h"

#include <QActionGroup>

MyApp::MyApp(QWidget *parent) :
    QMainWindow(parent),
    ui(new Ui::MyApp),
    sections(new QActionGroup(this)),
{
    ui->setupUi(this);

    /* Populate section list */

    /* Page indices for the stack widget*/
    ui->actionSectionOne->      setData(0);
    ui->actionSectionTwo->      setData(1);
    ui->actionSectionThree->    setData(2);

    sections->addAction(ui->actionSectionOne);
    sections->addAction(ui->actionSectionTwo);
    sections->addAction(ui->actionSectionThree);


    ui->mainToolBar->addSeparator();

    connect(sections, SIGNAL(triggered(QAction*)), this, SLOT(showSection(QAction*)));

    /* Show the default section */
    ui->actionContentSection->trigger();
}

MyApp::~MyApp()
{   
    delete ui;  
}

void MyApp::showSection(QAction *a)
{
    ui->mainArea->setCurrentIndex(a->data().toInt());
}