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Home/ Questions/Q 7875305
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Editorial Team
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Editorial Team
Asked: June 3, 20262026-06-03T02:57:38+00:00 2026-06-03T02:57:38+00:00

i am new to shell scripting and i found following line of code in

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i am new to shell scripting and i found following line of code in a given script.

could someone explain me what does the following lines of codes means

  1. _filecount=echo ${_filelist} | wc -w | awk '{ print $1 }'

  2. printk "archiveWLS(): ${_filecount} file(s)"

Thanks in advance for any help

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  1. Editorial Team
    Editorial Team
    2026-06-03T02:57:39+00:00Added an answer on June 3, 2026 at 2:57 am
    _filecount=echo ${_filelist} | wc -w | awk '{ print $1 }'
    

    wc -w: wc is word-count, wordcount counts words, lines, characters and so on, -w only outputs the word count.

    The output is piped to awk, to print only the first word of output. If you use

     wc -w FILE 
    

    the filename would be printed, and it would make sense to strip it away with awk. Doing it with a piped output, where there is no filename, is superflous.

    As assignment, the line should instead be:

    _filecount=$(echo ${_filelist} | wc -w )
    

    Without $(…) or backticks, it doesn’t work, and filecount is just assigned the word “echo”. Seems like a poorly written script.

    printk isn’t defined in bash, nor is it a well established gnu programm from the coreutils.

    Maybe it is defined in the script itself.

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