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Home/ Questions/Q 8665073
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Editorial Team
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Editorial Team
Asked: June 12, 20262026-06-12T17:23:42+00:00 2026-06-12T17:23:42+00:00

I am new to using QT and relatively new to C++. I have a

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I am new to using QT and relatively new to C++. I have a vector called drives that holds all of the drive letters of a computer. I have an int called noDrives which is drives.size(); I have set in my form in QT Designer 9 Progress bars which I will set all to invisible using

   ui.driveLabel1->setVisible(false); 

I have forgotten how I would go about setting the bars to visible in a for loop. e.g. int drives = 4 so I need to turn progressBar0-4 to visible. here is what I have so far.

    std::vector<std::string> drives = DriveFinder();
    int noDrives = drives.size();
    for (int i = 0 ; i < noDrives ; i++){
    ui.driveBar1->setVisible(false);
    }

Each time around the loop I need to turn on the next driveBar.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-12T17:23:44+00:00Added an answer on June 12, 2026 at 5:23 pm

    If I am understanding your question correctly:

    switch( i )
    {
     case 1: ui.driveBar1->setVisible(false); break;
     case 2: ui.driveBar2->setVisible(false); break;
     case 3: ui.driveBar3->setVisible(false); break;
     ...
    }
    

    Or

    std::vector<QProgressBar*> Bars (10);
    Bars[0] = ui.driveBar1;
    Bars[1] = ui.driveBar2;
    ...
    

    Then…

    Bars[i]->setVisible(false);
    
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