Question

I am new to web programming and this is my first SO question, so hopefully I am asking the right way. I am building a simple survey-maker (similar to google forms or survey monkey) and I have a web form that allows the user to add options to a question. Each option has two fields, ‘label’ and ‘value’. The form looks like this:

    Option One
           ------------------           ------------------
    Label: |                |   Value:  |                |
           ------------------           ------------------

    Option Two
           ------------------           ------------------
    Label: |                |   Value:  |                |
           ------------------           ------------------
    ...
    ...
    ... // user can "add option" and additional "rows" will appear in the form

[ SUBMIT ]

I have used a basic web form like this:

<form class="well form" action="/submitform" method="post">
  <p><input type="text" name="label_1">
     <input type="text" name="value_1"></p>
  <p><input type="text" name="label_2">
     <input type="text" name="value_2"></br></p>
  <p>...   // and so forth, to support n sets of two fields
     ...
     ...
  <button type="submit">Submit</button>
</form>

I successfully get request.form and can access each variable in the dict. But of course it’s a single flat dict:

[{'label_1': 'labelone', 'value1': 'valueone', 'label_2': 'label two'}]

and so forth. I want a list of dicts like this:

[ {'label': 'labelone', 'value': 'valueone'}, {'label': 'labeltwo', 'value': 'valuetwo'}]

I’ve thought of several hackish ways to do this, but all require foreknowledge of the number and type of form options. I’d rather find a more flexible solution.

Any best practice here? A lot of sites do things like this so I’m guessing there’s a best practice that I’m missing.

Answer 1

What about this?

l = [{'label_1': 'labelone', 'value_1': 'valueone', 'label_2': 'label two', 'value_2':'v2'}]

values = int(len(l[0])/2)
dicts = []
for i in range(values):
    label_name = 'label_%s' % (i+1)
    value_name = 'value_%s' % (i+1)
    dicts.append({'label':l[0][label_name], 'value':l[0][value_name]})