Question

I am not able to send the data on the second instance. The server just waits infinitely for client data
Here is my sample server code snippet:

ServerSocket serv = new ServerSocket(6789);
    Socket soc = serv.accept();
    System.out.println("waiting for client's input");       
    BufferedReader in = new BufferedReader(new InputStreamReader(soc.getInputStream()));
    DataOutputStream out = new DataOutputStream(soc.getOutputStream());
    String indata=in.readLine();
    System.out.println("The client says: "+indata+"\n Send them some data: ");
    String datum="demodata";        
    out.writeBytes(datum);
    System.out.println("Data sent");

Sample Client:

ocket soc = new Socket("localhost",6789);

    BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
    BufferedReader in = new BufferedReader(new InputStreamReader(soc.getInputStream()));
    DataOutputStream out = new DataOutputStream(soc.getOutputStream());     
    System.out.println("Connected to: "+soc.getLocalAddress() +"\nEnter data to be sent: ");        
    String outdata = br.readLine(); //take input    
    out.writeBytes(outdata); // send 
    String indata=in.readLine(); //read
    System.out.println("Data Sent! Now reading data from server "+indata)

Please tell me my problem! Thanks in advance

Answer 1

Answer is quite simple. You want to exchange lines of text between server and client.

The correct part is on the server side:

String indata=in.readLine();

The wrong part is on the client side:

out.writeBytes(outdata); // send 

I haven’t tested the code, but it seems you are just sending some data and your server side waits for \n (newline escape sequence) to appear.

Option 1:
Construct a PrintWriter and call the corresponding println method.

Option 2:
Append a newline (\n) manually.

Afterwards, readLine on the server side will recognize the line terminated by \n and will proceed.