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Home/ Questions/Q 6771551
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T15:26:44+00:00 2026-05-26T15:26:44+00:00

I am not able to understand the following behavior of StringBuilder when NULL objects

  • 0

I am not able to understand the following behavior of StringBuilder when NULL objects are appended to an instance:

public class StringBufferTest {

    /**
     * @param args
     */
    public static void main(String[] args) {
        String nullOb = null;
        StringBuilder lsb = new StringBuilder();

        lsb.append("Hello World");
        System.out.println("Length is: " + lsb.length());// Prints 11. Correct

        lsb.setLength(0);
        System.out.println("Before assigning null" + lsb.length());    
        lsb.append(nullOb);
        System.out.println("Length now is:" + lsb.length()); // Prints 4. ???
    }

}

The last print statement does not print 0. Can anyone please help me understand the behavior?

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  1. Editorial Team
    Editorial Team
    2026-05-26T15:26:45+00:00Added an answer on May 26, 2026 at 3:26 pm

    From the StringBuffer API –

    http://download.oracle.com/javase/1.5.0/docs/api/java/lang/StringBuffer.html#append(java.lang.String)

    The characters of the String argument are appended, in order,
    increasing the length of this sequence by the length of the argument.
    If str is null, then the four characters “null” are appended.

    This should explain the length as 4.

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