Question

I am not able to understand why

float x = (4+2%-8);
printf("%f\n", x);

prints 6.000000 and

printf("%f\n", (4+2%-8));

prints 0.000000. Any information will be helpful.
Regards.

Answer 1

The expression (4 + 2 % -8) produces an integer and you are trying to print a float (and they don’t match).

In the first case the integer is converted to float (because of the assignment) so later on the printf works because the value is in a format %f expects.

Try this:

printf("%f\n", (4.0 + 2 % -8));
                 ^