Question

I am not sure if what I am trying to do is even possible, but I figure there must be some work around for it. Assume two routines; routine A and routine B. Both routines A, and B have their own try-catch statements. Routine A will call routine B (shown below), and if routine B encounters some error, routine A will be notified of it.

Here is my example:

// Routine A
private void button13_Click(object sender, EventArgs e)
{
    try
    {
        somevoid();
    }
    catch(Exception ex)
    {
        Console.WriteLine(ex.message); // Never makes it here ...
    }
}

// Routine B
private void somevoid()
{
    try
    {
        int i = 1;
        int z = 0;
        int g = i / z;
    }
    catch (Exception ex)
    {
        Console.WriteLine(ex.Message);
    }
}

Answer 1

I am not sure what you want to achieve, but it seems, you need to catch the exception in both try catch blocks. If so, change your code as follows:

private void somevoid()
        {

            try
            {
                int i = 1;
                int z = 0;
                int g = i / z;
            }

            catch (Exception ex)
            {
                Console.WriteLine(ex.Message);
                throw;
            }
        }