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Home/ Questions/Q 9119959
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Editorial Team
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Editorial Team
Asked: June 17, 20262026-06-17T05:31:11+00:00 2026-06-17T05:31:11+00:00

I am not writing my exact code here but I am giving the basic

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I am not writing my exact code here but I am giving the basic idea.

<form action="thispageagain.php">

for($i=0; $i<$n; $i++){
echo "<input type=\"submit\" value=\"view post\" />";
}

</form>

Now when someone click on view post i have to send post id for that post. How can I do this. I have to use post method here.

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  1. Editorial Team
    Editorial Team
    2026-06-17T05:31:12+00:00Added an answer on June 17, 2026 at 5:31 am

    you need to send the post id right… if i did not get your question wrong then you can do it as follow.. i assume that $i represents your post id that you want to send.

    <?php
      if(isset($_POST['formsubmitted']) && $_POST['formsubmitted'] === 'Y'){
          $postId = array_keys($_POST['btnviewPost']);
          print_r( $postId);
      }
    ?>
    <form action="" method="post">
     <input type="hidden" name="formsubmitted" value="Y" />
     <?php for($i=0;$i<$n;$i++){?>
        <input type="submit" value="view post" name="btnviewPost[<?php echo $i?>]" />
     <?php }?> 
    </form>
    
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