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Home/ Questions/Q 3664840
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Editorial Team
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Editorial Team
Asked: May 19, 20262026-05-19T01:41:31+00:00 2026-05-19T01:41:31+00:00

I am opening Maps app to show directions from user’s Current Location to a

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I am opening Maps app to show directions from user’s Current Location to a destination coordinate, from my code. I am using the following code to open the Maps app. I am calling this code when a button is pressed. getCurrentLocation is a method that returns the recently updated location.

- (void)showDirectionsToHere {

    CLLocationCoordinate2D currentLocation = [self getCurrentLocation];  // LINE 1
    NSString* url = [NSString stringWithFormat: @"http://maps.google.com/maps?saddr=%f,%f&daddr=%f,%f", 
                                                  currentLocation.latitude,
                                                  currentLocation.longitude, 
                                                  destCoordinate.latitude, 
                                                  destCoordinate.longitude];
    [[UIApplication sharedApplication] openURL:[NSURL URLWithString:url]];
}

Here [self getCurrentLocation] in LINE 1 uses CLLocationManager to determine the Current Location and returns the value.

Note: I have not yet implemented the code in LINE1. I’ve just planned to do it that way.

My questions are:

  1. Is this good practice to calculate the Current Location, at the time the Maps app is called?
  2. Will [self getCurrentLocation] return the Current Location before openURL gets called?
  3. Do I have to determine the Current Location well before opening the Maps app?

I am little bit confused about these things. Kindly guide me. Thanks.

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  1. Editorial Team
    Editorial Team
    2026-05-19T01:41:32+00:00Added an answer on May 19, 2026 at 1:41 am

    You don’t have to determine the user’s current location yourself, the Maps app will take care of it.

    Instead of passing a latitude/longitude pair you can pass Current%%20Location and Maps will determine the user’s current location itself.

    %20 is a url-encoded space character, and the extra % escapes the actual % so it won’t be interpreted as a format substitution.


    Thanks to @Carlos P for pointing out my escape character blunder in the original answer.

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