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Home/ Questions/Q 877691
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T11:39:06+00:00 2026-05-15T11:39:06+00:00

I am opening up a binary file like so: file = open(test/test.x, ‘rb’) and

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I am opening up a binary file like so:

file = open("test/test.x", 'rb')

and reading in lines to a list. Each line looks a little like:

'\xbe\x00\xc8d\xf8d\x08\xe4.\x07~\x03\x9e\x07\xbe\x03\xde\x07\xfe\n'

I am having a hard time manipulating this data. If I try and print each line, python freezes, and emits beeping noises (I think there’s a binary beep code in there somewhere). How do I go about using this data safely? How can I convert each hex number to decimal?

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  1. Editorial Team
    Editorial Team
    2026-05-15T11:39:07+00:00Added an answer on May 15, 2026 at 11:39 am

    To print it, you can do something like this:

    print repr(data)
    

    For the whole thing as hex:

    print data.encode('hex')
    

    For the decimal value of each byte:

    print ' '.join([str(ord(a)) for a in data])
    

    To unpack binary integers, etc. from the data as if they originally came from a C-style struct, look at the struct module.

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