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Home/ Questions/Q 6540929
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T11:02:28+00:00 2026-05-25T11:02:28+00:00

I am parsing an xml which looks like this <title>abc</title> <summary>abc</summary> <content type=’application/atom+xml’ src=’abc’/>

  • 0

I am parsing an xml which looks like this

<title>abc</title>
<summary>abc</summary>
<content type='application/atom+xml' src='abc'/>
<link rel='alternate' type='application/atom+xml' href='abc'/>
<title>abc</title>
<summary>xyz</summary>
<content type='application/atom+xml' src='xyz'/>
<link rel='alternate' type='application/atom+xml' href='xyz'/>
<title>abc</title>
<summary>abb</summary>
<content type='application/atom+xml' src='abb'/>
<link rel='alternate' type='application/atom+xml' href='abb'/>

My jQuery:

$title.each(function(index)
  {
    if (index != 0) 
        {
          $("#container").append('<div id=' + index + '></div></br>');
      $('#' + index).text($(this).text());
      $srcnode = $(xml).find('content')[index];
      alert($srcnode.attr('src'));
    }
}

I am getting the error as no attr ‘src’ found for the element. I am trying to fetch the link corresponding to the title which is in content

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-25T11:02:28+00:00Added an answer on May 25, 2026 at 11:02 am

    try to change

      $srcnode = $(xml).find('content')[index];
    

    to

      $srcnode = $(xml).find('content').eq(index);
    

    (+ you have no “xml” variable.) After you correct it,
    it should work correctly then

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