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Home/ Questions/Q 8807319
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Editorial Team
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Editorial Team
Asked: June 14, 20262026-06-14T02:20:27+00:00 2026-06-14T02:20:27+00:00

I am passing this url String urlForLineChart =http://chart.apis.google.com/chart? + cht=lc& + chs=200×125& + chxl=0%3a|1|2|3|4|5|6|7|8|9|10&+

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I am passing this url

String urlForLineChart ="http://chart.apis.google.com/chart?" +
                "cht=lc&" +
                "chs=200x125&" +
                "chxl=0%3a|1|2|3|4|5|6|7|8|9|10&"+
                "chd=t:10,3,5,8,15,20&"+                                
                "chxt=x,y&"+
                "chds=0,50&"+
                "chxr=0,0,16%7C1,0,50&"+
                "chm=s,FF0000,1,0,5";

To make a chart but it is not represent desired result kindly help me.
I am not getting that how to pass parameters. I searched a lot.


I am doing as follows

WebView mCharView = (WebView) findViewById(R.id.char_view);
mCharView.loadUrl(urlForLineChart);
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  1. Editorial Team
    Editorial Team
    2026-06-14T02:20:29+00:00Added an answer on June 14, 2026 at 2:20 am

    You must enable Javascript in your webview:

     webview = (WebView) findViewById(R.id.webview);
     webview.getSettings().setJavaScriptEnabled(true);
    
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