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Home/ Questions/Q 6233237
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Editorial Team
  • 0
Editorial Team
Asked: May 24, 20262026-05-24T10:15:45+00:00 2026-05-24T10:15:45+00:00

I am planing to display Rss feed inside an Androind app I have this

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I am planing to display Rss feed inside an Androind app

I have this Rss feed url http://yofreesamples.com/category/free-coupons/feed/
I do not have control or access to the RSS feeds.

JSONP is the solution for requests that respond with JSON output. But here, I have RSS feeds which can respond with pure xml .

I have a constraint of not using a proxy to retrieve rss feeds. I tried to implement with Google AJAX Feed API but I ran into a problem. I need to get the value of entry_title
which is inside the call back function and use it in my other function which displays a system notification inside the android app , but I am unable to get the value and I dont want to use any containers and display it inside a div. Is there a way to get this value or Is there a client-only workaround for this problem

/* ---------------------- global variables ---------------------- */
var entry;
/* ---------------------- end global variables ---------------------- */
    function getRss(url){ 

    if(url == null) return false;

    google.load("feeds", "1");

    // Our callback function, for when a feed is loaded.
    function feedLoaded(result) {
        if (!result.error) {
            // Check out the result object for a list of properties returned in each entry.
            // http://code.google.com/apis/ajaxfeeds/documentation/reference.html#JSON

            var entry = result.feed.entries[0];             
            var entry_title = entry.title;
        }
        entry = entry_title; // not working

    }


    function Load() {
        // Create a feed instance that will grab feed.
        var feed = new google.feeds.Feed(url);
        // Calling load sends the request off.  It requires a callback function.
        feed.load(feedLoaded);

    }

    google.setOnLoadCallback(Load);             
}
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-24T10:15:46+00:00Added an answer on May 24, 2026 at 10:15 am

    I modified your code a little and it works

    /* ---------------------- global variables ---------------------- */
    var entry;
    /* ---------------------- end global variables ---------------------- */
    function getRss(url){ 
    
        if(url == null) return false;
    
        google.load("feeds", "1");
    
        // Our callback function, for when a feed is loaded.
        function feedLoaded(result) {
            if (!result.error) {
                // Check out the result object for a list of properties returned in each entry.
                // http://code.google.com/apis/ajaxfeeds/documentation/reference.html#JSON
    
                entry = result.feed.entries[0];             
            }
            // pass it to other function
            someFunction(entry.title);
        }
    
        function Load() {
            // Create a feed instance that will grab feed.
            var feed = new google.feeds.Feed(url);
            // Calling load sends the request off.  It requires a callback function.
            feed.load(feedLoaded);
        }
    
        // some function
        function someFunction(s) {
            alert(s);
        }
    
        google.setOnLoadCallback(Load);             
    }
    
    // calling it ?
    getRss("http://yofreesamples.com/category/free-coupons/feed/");
    
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