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Home/ Questions/Q 6829367
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T22:29:31+00:00 2026-05-26T22:29:31+00:00

I am porting a C++ utility to C#. When I run the following statement

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I am porting a C++ utility to C#. When I run the following statement in C++, I get the correct operation. When I run the same statement in C#, however…

omgwtfbbq

Does anyone know why ‘begin++’ is executed? The crazy thing is that if I run (i % 2) == 0 with i=0, the Immediate Window returns true.

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  1. Editorial Team
    Editorial Team
    2026-05-26T22:29:32+00:00Added an answer on May 26, 2026 at 10:29 pm

    Operator precedence is irrelevant in this question. It’s evaluation order that causes this behavior.

    In C# i++ is evaluated before i % 2 since it’s on the left side. Thus i % 2 is false and the right side of the if gets evaluated.

    First you use precedence to get the syntax tree:

    =
      buffer[i++]
      if i % 2
        then temp[end--]
        else temp[begin++]
    

    On each node you evaluate the children from left to right. This implies that i++ is evaluated before i % 2.

    Eric Lippert has plenty of posts on this, both here on SO, and on his blog:

    • Precedence vs Associativity vs Order
    • Precedence vs order, redux

    Personally I’d avoid such code. It’s much nicer to split it into multiple expressions, or even use a plain if statement instead of ? :


    In C++ accessing a variable that was written to without a sequence point in between is undefined behavior. I think = is no sequence point, so I guess your expression is undefined in C++ and just happened to work.

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