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Home/ Questions/Q 8181421
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Editorial Team
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Editorial Team
Asked: June 7, 20262026-06-07T00:30:53+00:00 2026-06-07T00:30:53+00:00

I am pretty new to PHP and MySQL and I just can’t figure this

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I am pretty new to PHP and MySQL and I just can’t figure this one out. I have searched all around the forum but haven’t found an answer I can make sense of. I originally was using mysql_fetch_assoc() but I could only search numbers and I received errors when searching for letters as well. I hope I am on the right track here. Thank you in advance for all your help!

$con = mysqli_connect($hostname,$username,$password) or die ("<script language='javascript'>alert('Unable to connect to database')</script>");
mysqli_select_db($con, $dbname);

if (isset($_GET['part'])){
    $partid = $_GET['part'];
    $sql = 'SELECT * 
        FROM $usertable 
        WHERE PartNumber = $partid';

    $result = mysqli_query($con, $sql);
    $row = mysqli_fetch_assoc($result);

    $partnumber = $partid;
    $nsn = $row["NSN"];
    $description = $row["Description"];
    $quantity = $row["Quantity"];
    $condition = $row["Conditio"];
}
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  1. Editorial Team
    Editorial Team
    2026-06-07T00:30:57+00:00Added an answer on June 7, 2026 at 12:30 am

    This happens when your result is not a result (but a "false" instead).
    You should change your code to this

    $sql = 'SELECT * 
        FROM usertable 
        WHERE PartNumber = ?';
    
    $stmt = $con->prepare($sql);
    $stmt->bind_param("s", $partid);
    $stmt->execute();
    $result = $stmt->get_result();
    $row = mysqli_fetch_assoc($result);
    

    because you shouldn’t add data variables in the SQL directly, but use placeholders instead. Given a placeholder cannot be used for a table name, it is generally a bad idea to make it a variable, so just write it as is.

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