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Home/ Questions/Q 3483042
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Editorial Team
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Editorial Team
Asked: May 18, 20262026-05-18T10:37:40+00:00 2026-05-18T10:37:40+00:00

I am pretty sure that what I am doing here is right, but I

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I am pretty sure that what I am doing here is right, but I just wanted to check that the [cell autorelease] is not freeing my cells too soon and that dequeueReusableCellWithIdentifier has queued cells around waiting for reuse. My understanding is that the queue is a separate entity in as much as its storing a blueprint for the cell (a bit like a nib) and not the actual object?

- (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath {
    UITableViewCell *cell = [tableView dequeueReusableCellWithIdentifier:@"LOC_ID"];
    if(cell == nil) {
        cell = [[UITableViewCell alloc] initWithStyle:UITableViewCellStyleDefault reuseIdentifier:@"LOC_ID"];
        [cell autorelease];
    }
    NSUInteger row = [indexPath row];
    //id thisLocation = [locationList objectAtIndex:row];
    [[cell textLabel] setText:[NSString stringWithFormat:@"R_%u", row]];
    return cell;
}

EDIT: To clarify I am interested in the what happens with regard to lifespan and the cells. I understand that I alloc them and then autorelease them, does the table then take ownership of the cells after they are returned from cellForRowAtIndexPath? so they ten belong to the UITableView, or am I getting confused?

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  1. Editorial Team
    Editorial Team
    2026-05-18T10:37:41+00:00Added an answer on May 18, 2026 at 10:37 am

    No it is actually storing the cell object per identifier.

    When the table first gets created the cell is created from scratch.
    So when you scroll the tableview, the new cells are dequeued based on the identifier. For performance reasons, it can be reused by for example, setting text on the cell; so there is no need to create a new cell from scratch.

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