Question

I am producing multiple forms from my php code as shown below.

The problem is that, If I want to perform a jquery-ajax request, How can I refer to a form. My goal is that when the submit button is clicked, the relevant data from that form should be posted.

Previously, I was referring to form with its $('#id').submit() function. But I am stuck here since all of the forms have the same name.

<form id="view-doc" method="post" target="report" action="../classes/openDoc.php">
<input type="hidden" id="id" name="id" value="1"/>
<input type="hidden" id="filename" name="filename" value="Research Writer Test 8.doc" />
<input type="hidden" id="filetype" name="filetype" value="doc" />
<td><input type="submit" class="s-button btn_normal" id="submit" value="View" onsubmit="window.open(about:blank,report,width=300,height=200)" />
</form>

<form id="view-doc" method="post" target="report" action="../classes/openDoc.php">
<input type="hidden" id="id" name="id" value="2"/>
<input type="hidden" id="filename" name="filename" value="template[1].IEEEdoc.doc" />
<input type="hidden" id="filetype" name="filetype" value="doc" />
<input type="submit" class="s-button btn_normal" id="submit" value="View" onsubmit="window.open(about:blank,report,width=300,height=200)" />
</form>

<form id="view-doc" method="post" target="report" action="../classes/openDoc.php">
<input type="hidden" id="id" name="id" value="3"/>
<input type="hidden" id="filename" name="filename" value="Assignment #3.docx" />
<input type="hidden" id="filetype" name="filetype" value="ocx" />
<input type="submit" class="s-button btn_normal" id="submit" value="View" onsubmit="window.open(about:blank,report,width=300,height=200)" />
</form>

Answer 1

id attribute has to be unique. If possible please consider view-doc-1, view-doc-2 and view-doc-3 for the forms’ id.

Otherwise, use class instead of id and do this on JavaScript:

$(".view-doc input[type=submit]".bind('click', function() {
   // your code when button clicked. fired on all the 3 buttons
});