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Home/ Questions/Q 8855927
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Editorial Team
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Editorial Team
Asked: June 14, 20262026-06-14T14:14:44+00:00 2026-06-14T14:14:44+00:00

I am puzzled about the variable substitution in shell scripting. Here is the deal:

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I am puzzled about the variable substitution in shell scripting. Here is the deal: I have following script.

if [ -d ~someone/Desktop ]
then
    echo exist
fi

which would determine whether user “someone” has “Desktop” directory under his home directory. However, if I substitute the someone by other variable, it will not be correct. See below,

var=someone
if [ -d ~${var}/Desktop ]
then
    echo exist
fi

Although the user “someone” has Desktop directory, it will not print exist in the output. Can someone tell me why this happened?

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  1. Editorial Team
    Editorial Team
    2026-06-14T14:14:46+00:00Added an answer on June 14, 2026 at 2:14 pm
    var=someone
    if [ -d $(eval echo ~${var})/Desktop ]
    then
        echo exist
    fi
    
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