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Home/ Questions/Q 7022863
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T23:38:13+00:00 2026-05-27T23:38:13+00:00

I am quite confused on whether where to look for the solution on this

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I am quite confused on whether where to look for the solution on this one. I initially used DateTime::diff to this problem, however, the server this time has PHP version < 5.3.

I am calculating time difference,

$beyond= $_POST['beyond']; // 2012-01-07
$here= $_POST['here']; //2012-01-14
$interval = abs(strtotime($beyond) - strtotime($here));

The output of this is 604800, I want to output this into string with a value of +7 or simply 7.

Thanks.

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  1. Editorial Team
    Editorial Team
    2026-05-27T23:38:14+00:00Added an answer on May 27, 2026 at 11:38 pm

    I think this can help you:

    $beyond= "2012-01-07";
    $here= "2012-01-15";
    $interval = abs(strtotime($here) - strtotime($beyond));
    
    $interval/= 86400;
    
    echo round($interval);
    

    Just get the time and divide for a day (86400 secunds in a day).

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