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Home/ Questions/Q 724533
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T06:14:01+00:00 2026-05-14T06:14:01+00:00

I am reading a book called Teach Yourself C in 21 Days (I have

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I am reading a book called “Teach Yourself C in 21 Days” (I have already learned Java and C# so I am moving at a much faster pace). I was reading the chapter on pointers and the -> (arrow) operator came up without explanation. I think that it is used to call members and functions (like the equivalent of the . (dot) operator, but for pointers instead of members). But I am not entirely sure.

Could I please get an explanation and a code sample?

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  1. Editorial Team
    Editorial Team
    2026-05-14T06:14:02+00:00Added an answer on May 14, 2026 at 6:14 am

    foo->bar is equivalent to (*foo).bar, i.e. it gets the member called bar from the struct that foo points to.

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