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Home/ Questions/Q 717557
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T05:25:35+00:00 2026-05-14T05:25:35+00:00

I am reading Java Concurrency in practice and looking at the example code on

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I am reading “Java Concurrency in practice” and looking at the example code on page 51.

This states that if a thread has references to a shared object then other threads may be able to access that object before the constructor has finished executing.

I have tried to put this into practice and so I wrote this code thinking that if I ran it enough times a RuntimeException(“World is f*cked”) would occur. But it isn’t doing.

Is this a case of the Java spec not guaranting something but my particular implementation of java guaranteeing it for me? (java version: 1.5.0 on Ubuntu) Or have I misread something in the book?

Code: (I expect an exception but it is never thrown)

public class Threads {
 private Widgit w;

 public static void main(String[] s) throws Exception {
  while(true){
   Threads t = new Threads();
   t.runThreads();
  }
 }

 private void runThreads() throws Exception{
  new Checker().start();
  w = new Widgit((int)(Math.random() * 100)  + 1);
 }

 private class Checker extends Thread{
  private static final int LOOP_TIMES = 1000;

  public void run() {
   int count = 0;
   for(int i = 0; i < LOOP_TIMES; i++){
    try {
     w.checkMe();
     count++;
    } catch(NullPointerException npe){
     //ignore
    }
   }
   System.out.println("checked: "+count+" times out of "+LOOP_TIMES);
  }
 }

 private static class Widgit{
  private int n;
  private int n2;

  Widgit(int n) throws InterruptedException{
   this.n = n;
   Thread.sleep(2);
   this.n2 = n;
  }

  void checkMe(){
   if (n != n2) {
    throw new RuntimeException("World is f*cked");
   }
  }
 }

}
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-14T05:25:36+00:00Added an answer on May 14, 2026 at 5:25 am

    Well, you need to understand the issues a little more. It isn’t really a case of anything being or not being “guaranteed.” With concurrency problems, nothing is really guaranteed unless you really do specific things to force the problem to happen. You’re just relying on the hope that enough runs should produce, which is not the case. These kinds of problems are hard to predict, which is why concurrency is a hard problem. You could try doing more work in your functions, but I assure you these are real problems that the runtime is not going to save you from.

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