Question

I am reading javascript web application and the author is using following code:

mod.load = function(func){
    $($.proxy(func, this));
};

Can someone help me to understand why returning function from jQuery.proxy is inside jQuery wrapper.

Is this the same as:

mod.load = function(func){
    var temp = $.proxy(func, this);
    temp();
};

Answer 1

They are not the same but they have the same effect. Your second example executes the returned function directly while jQuery(function) binds it to the onload like $(document).ready(). mod.load probably is the onload however, so this makes no difference.

See http://api.jquery.com/jQuery/#jQuery3